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Mistake #1: Incorrect: 43 = 4 × 3 Correct: 43 = 4 × 4 × 4 Mistake #2: Incorrect: -32 = -3 × -3 = 9 Correct: -(3 × 3) = -9 Mistake #3: Incorrect: 80 = 0 Correct: 80 = No answer! Mistake #4: Incorrect: -5 + 15 = -20 Correct: -5 + 15 = 10 Mistake #5: Incorrect: √9 + 16= √9+ √16 = 3 + 4 = 7 Correct: √9 + 16= √25 = 5 Mistake #6: Incorrect: x + 8 > 10 x + 8 - 8 < 10 - 8 x = 2 Correct: x + 8 > 10 x + 8 - 8 > 10 - 8 x > 2 Mistake #7: Incorrect: y3 × y2 = y6 Correct: y3 × y2 = y5 | Mistake #8: Incorrect: (2y)4 = 2y4 Correct: (2y)4 = 16y4 Mistake #9: Incorrect: 4 × (2z + 5) = 4 × 2z + 5 Correct: 4 × (2z + 5) = 4 × 2z + 4 × 5 Mistake #10: Incorrect: x + 10 = 20 x + 10 - 10 = 20 - 10 0 = 10 Correct: x + 10 = 20 x + 10 - 10 = 20 - 10 x + 0 = 10 Mistake #11: Incorrect: 6x + 36x + 2= 32 Correct: 6x + 36x + 2 = 6x + 36x + 2 Mistake #12: Incorrect: x + 10 = 20 x + 10 - 10 = 20 - 10 0 = 10 Correct: x + 10 = 20 x + 10 - 10 = 20 - 10 x + 0 = 10 |
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We very often get a feeling that the addtion done can have correct answer or ti may be wrong also in this post i am trying to explain how can we verify the anwer just doing sum of digits
A way to check additions doneAddition of the Digit Sum of the numbers to be multiplied should be equal to the digit sum of the answer.
For eg. 23 + 64 = 87.
Digit sum of 23 = 2+3 = 5; 64 = 6+4 = 10 = 1+0 = 1. So Total 5+1 = 6
Digit sum of 87 = 8+7 = 15 = 1+5 = 6.
Addition of digit sum of the numbers = 5+1 = 6.
Vedic Maths can be a mighty weapon when the question of speed arises while doing a problem. But one must be well versed and practised in its tricks in order to apply them without any doubt. There is no use in doing a problem through Vedic Maths and then doing the normal method to verify it. That wouldn’t save any time. Hence, as they say, practice makes you perfect!
A way to check additions doneAddition of the Digit Sum of the numbers to be multiplied should be equal to the digit sum of the answer.
For eg. 23 + 64 = 87.
Digit sum of 23 = 2+3 = 5; 64 = 6+4 = 10 = 1+0 = 1. So Total 5+1 = 6
Digit sum of 87 = 8+7 = 15 = 1+5 = 6.
Addition of digit sum of the numbers = 5+1 = 6.
Vedic Maths can be a mighty weapon when the question of speed arises while doing a problem. But one must be well versed and practised in its tricks in order to apply them without any doubt. There is no use in doing a problem through Vedic Maths and then doing the normal method to verify it. That wouldn’t save any time. Hence, as they say, practice makes you perfect!
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- Figure This! Math challenges
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- Virtual Math Club
- Natural Math community and projects
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- Math Helpers
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- Algebra Help
- Nick's Mathematical Puzzles
- Practical Money Skills
- Multiplication.com's online games
- PBS Teachers Math
- Web Math
- Math Fact Cafe
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- The Math Forum
- IXL Math (daily practice limit for free use but excellent for K-8 math practice, aligned with standards)
- Math Fun Facts
- Math Monday
- I Love That Teaching Idea! Math Ideas
Let me know if i have missed some links so that i can update the list.
Friends, this time it has been a long time I have written a post. I badly wanted to write one but because of very busy schedule I couldn’t.
This post is one of the many areas where Vedic Mathematics really surpasses traditional methods as you shall soon see. This post is about dividing any number by 9.
We will start by taking an example
Divide 200103002 by 9
We can initiate solving this problem by writing it as below -
9) 2 0 0 1 0 3 0 0 | 2
The symbol in front of the final 2 is not the number “1”, but a vertical bar “|”. This last position will hold the remainder, if any.
There are only two steps in this procedure.
Step 1: Bring down the 2. It will look like this:
9) 2 0 0 1 0 3 0 0 | 2
2
Step 2: Add the answer so far, the “2”, to the number on the upper right. For this example, we would add the “2” from the answer to “0”, the number on the above right. So we have:
9) 2 0 0 1 0 3 0 0 | 2
2 2
Now just repeat this process. Add the 2 to the 0, add the 2 to the 1, etc. We will end up with:
9) 2 0 0 1 0 3 0 0 | 2
2 2 2 3 3 6 6 6 | 8
This post is one of the many areas where Vedic Mathematics really surpasses traditional methods as you shall soon see. This post is about dividing any number by 9.
We will start by taking an example
Divide 200103002 by 9
We can initiate solving this problem by writing it as below -
9) 2 0 0 1 0 3 0 0 | 2
The symbol in front of the final 2 is not the number “1”, but a vertical bar “|”. This last position will hold the remainder, if any.
There are only two steps in this procedure.
Step 1: Bring down the 2. It will look like this:
9) 2 0 0 1 0 3 0 0 | 2
2
Step 2: Add the answer so far, the “2”, to the number on the upper right. For this example, we would add the “2” from the answer to “0”, the number on the above right. So we have:
9) 2 0 0 1 0 3 0 0 | 2
2 2
Now just repeat this process. Add the 2 to the 0, add the 2 to the 1, etc. We will end up with:
9) 2 0 0 1 0 3 0 0 | 2
2 2 2 3 3 6 6 6 | 8
Try a little advanced problem
9) 3 2 3 6 0 5 2 | 2
Step 1: Bring down the first number in the divisor.
9) 3 2 3 6 0 5 2 | 2
3
Step 2: Add the number on the above right and repeat. If we get carrys, put them in and don’t worry about them for now. So we will have:
9) 3 2 3 6 0 5 2 | 2
3 5 8 14 14 19 21 | 23
So, what do we do with all this stuff? Any number that has a carry, needs to be added to the left. Let’s do this starting with the “21” just after the bar.
9) 3 2 3 6 0 5 2 | 2
3 5 9 5 6 1 1 | 23
Now, notice that the remainder of 23 needs to be reduced until it is below a 9. There are two multiples of 9 in 23 with 5 left over. Therefore, we carry over 2 to the other side of the bar and add it to the 1. We will then have the answer:
9) 3 2 3 6 0 5 2 | 2
3 5 9 5 6 1 3 | 5
There is a little more work involved, but, still a lot less than the conventional way.
9) 3 2 3 6 0 5 2 | 2
Step 1: Bring down the first number in the divisor.
9) 3 2 3 6 0 5 2 | 2
3
Step 2: Add the number on the above right and repeat. If we get carrys, put them in and don’t worry about them for now. So we will have:
9) 3 2 3 6 0 5 2 | 2
3 5 8 14 14 19 21 | 23
So, what do we do with all this stuff? Any number that has a carry, needs to be added to the left. Let’s do this starting with the “21” just after the bar.
9) 3 2 3 6 0 5 2 | 2
3 5 9 5 6 1 1 | 23
Now, notice that the remainder of 23 needs to be reduced until it is below a 9. There are two multiples of 9 in 23 with 5 left over. Therefore, we carry over 2 to the other side of the bar and add it to the 1. We will then have the answer:
9) 3 2 3 6 0 5 2 | 2
3 5 9 5 6 1 3 | 5
There is a little more work involved, but, still a lot less than the conventional way.
Can you tell me whats 45 x 45 = ?? or 65 x 65 = ?? or 85 x 85 = ??
You can Mentally solve the above problems after learning the trick that I am gonna teach you today.
You can Mentally solve the above problems after learning the trick that I am gonna teach you today.
So here goes the trick
For Example calculating whats 65 x 65 = ???,
Step 1 : We'll multiply the two last digits of each number
i.e. = 5 x 5 =25
Step 2: Increase 1st digit of any number by 1 & then multiply it with 1 digit of next number,
i .e 6 is increased by 1 so it becomes 7 & its product will be 7 x 6 = 42
Step 3: Append those numbers i.e. 42 25 & thats your answer.
For Example calculating whats 65 x 65 = ???,
Step 1 : We'll multiply the two last digits of each number
i.e. = 5 x 5 =25
Step 2: Increase 1st digit of any number by 1 & then multiply it with 1 digit of next number,
i .e 6 is increased by 1 so it becomes 7 & its product will be 7 x 6 = 42
Step 3: Append those numbers i.e. 42 25 & thats your answer.
Lets take another example to understand is better
For Example calculating whats 95 x 95 = ???,
Step 1 : We'll multiply the two last digits of each number
i.e. = 5 x 5 =25
Step 2: Increase 1st digit of any number by 1 & then multiply it with 1 digit of next number,
i .e 9 is increased by 1 so it becomes 10 & its product will be 10 x 9 = 90
Step 3: Append those numbers i.e. 90 25
For Example calculating whats 95 x 95 = ???,
Step 1 : We'll multiply the two last digits of each number
i.e. = 5 x 5 =25
Step 2: Increase 1st digit of any number by 1 & then multiply it with 1 digit of next number,
i .e 9 is increased by 1 so it becomes 10 & its product will be 10 x 9 = 90
Step 3: Append those numbers i.e. 90 25
Now i am sure you can find square of any number with multiple of 5 mentally just increase the number by 1 & multiply it with next digits 1 st number. Then just at last append 25 to it.
Note: you can only apply this trick to numbers ending with 5 only.
Note: you can only apply this trick to numbers ending with 5 only.
Author
A Math Lover!! I have trained students who used to fear from Maths and now are active participant in the Math Contest conducted all around the world
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